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The question is: 10 g of carbonic acid H2CO3 are dissolved in 150 g of water. Determine the% m / m concentration of that solution?
Answer: The% m / m concentration of that solution is 6.66%.
Explanation:
Given: Mass of solute = 10 g
Mass of solvent = 150 g
Formula used to calculate the %m/m is as follows.
[tex]Percent (m/m) = \frac{mass of solute}{mass of solvent} \times 100[/tex]
Substitute the values into above formula as follows.
[tex]Percent (m/m) = \frac{mass of solute}{mass of solvent} \times 100\\= \frac{10 g}{150 g} \times 100\\= 6.66%[/tex]
Thus, we can conclude that the% m / m concentration of that solution is 6.66%.