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A region of vacuum contains both a uniform electric field with magnitude E and a uniform magnetic field with magnitude B.
Part A What is the ratio E/B if the energy density for the magnetic field equals the energy density for the electric field? Express your answer in volts per meter-tesla to three significant figures. IVO ADV A O O ?
Part B If E = 750 V/m, what is B, in teslas, if the magnetic field and electric-field energy densities are equal? Express your answer in teslas. O ALQ * R O 2 ?


Sagot :

Answer:

A)    E / B = 2.99 10⁸  V/ mT,  B)     B = 2.50 10⁻⁶ T

Explanation:

A) the expressions for the energy densities are:

         u_E = ½ ε₀ E²

         u_B = ½ B² /μ₀

indicate that the two densities are equal

         ½ ε₀ E² = ½ B² /μ₀  

         E / B =  1 /[tex]\sqrt{\epsilon_o \ \mu_o }[/tex]

we calculate

         E / B = 1 / √( 8.85 10⁻¹² 4π 10⁻⁷

         E / B = 1 /√( 11.1212 10⁻¹⁸)

         E / B = 0.29986 10⁹9

         E / B = 2.99 10⁸  V/ mT

B) for this case E = 750 V / m, ask the magnetic field

         E / B =  1 /[tex]\sqrt{\epsilon_o \ \mu_o}[/tex]

         B = E [tex]\sqrt{\epsilon_o \ \mu_o}[/tex]

         

we calculate

        B = 750 √(8.85 10⁻¹² 4π 10⁻⁷

        B = 750 3.3348 10⁻⁹

        B = 2.50 10⁻⁶ T

  • The ratio E/B if the energy density for the magnetic field equals the energy density for the electric field

Energy densities can be expressed as

        u_E = ½ ε₀ E²

        u_B = ½ B² /μ₀

When the two densities are equal we use the formula

        ½ ε₀ E² = ½ B² /μ₀  

             E / B =  1 / μ₀  

             E / B = 1 / √( 8.85 10⁻¹² 4π 10⁻⁷)

             E / B = 1 /√( 11.1212 10⁻¹⁸)

             E / B = 0.29986 10⁹

             E / B = 2.99 10⁸  V/ mT

  • If the magnetic field and electric-field energy densities are equal and  E = 750 V / m, we can deduce that

      E / B =  1 / √ ξ₀ μ₀

       B = E √ ξ₀ μ₀

We substitute the values into the equation

        B = 750 √(8.85 10⁻¹² 4π 10⁻⁷)

        B = 750 3.3348 10⁻⁹

        B = 2.50 10⁻⁶ T

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