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Answer:
C(x,y) = (-28,13)
Step-by-step explanation:
If co-ordinates of points A(x1,y1) and (x2,y2) and C is the external point that divides the line AB in ratio m:n then,
[tex]C (x,y) = \frac{mx_2-nx_1}{m-n} , \frac{my_2-ny_1}{m-n}[/tex]
Given: A (-6, 3) & B (5, -2) in ratio 2 : 3
Substituting these values in above formula to C(x,y)
C (x,y) = \frac{2\times5-3(-6)}{2-3} , \frac{2(-2)-3(3)}{2-3}
Solving we get
C(x,y) = (-28,13)