Answered

Find the best answers to your questions with the help of IDNLearn.com's knowledgeable users. Our platform provides prompt, accurate answers from experts ready to assist you with any question you may have.

Triangle IJK, with vertices I(-9,-8), J(-5,-6), and K(-7,-3), is drawn on the coordinate grid below.

Sagot :

MrRoyalidn

Answer:

[tex]Area= 8[/tex]

Step-by-step explanation:

Given

[tex]I = (-9,-8)[/tex]

[tex]J = (-5,-6)[/tex]

[tex]K = (-7,-3)[/tex]

The complete part of the question is to calculate the area of IJK

The area is calculated using:

[tex]Area = \frac{1}{2}|x_1y_2 - x_2y_1 + x_2y_3 - x_3y_2 + x_3y_1 - x_1y_3 |[/tex]

Where:

[tex]I = (-9,-8)[/tex] --- [tex](x_1,y_1)[/tex]

[tex]J = (-5,-6)[/tex] --- [tex](x_2,y_2)[/tex]

[tex]K = (-7,-3)[/tex] --- [tex](x_3,y_3)[/tex]

So, we have:

[tex]Area = \frac{1}{2}|(-9*-6) - (-5*-8) + (-5*-3) - (-7*-6) + (-7*-8) - (-9*-3) |[/tex]

Solve the brackets

[tex]Area = \frac{1}{2}|54 - 40 + 15- 42 + 56 - 27 |[/tex]

[tex]Area = \frac{1}{2}|16|[/tex]

The absolute value of 16 is 16

So:

[tex]Area = \frac{1}{2} * 16[/tex]

[tex]Area= 8[/tex]

We are happy to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. Your questions deserve reliable answers. Thanks for visiting IDNLearn.com, and see you again soon for more helpful information.