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A +26.3 uC charge qy is repelled by a force
of 0.615 N from a second charge 92 that is
0.750 m away. What is the value of 92?
Include the sign of the charge (+ or -).
(u stands for micro.)
[?] x 10-6 C

A 263 UC Charge Qy Is Repelled By A Force Of 0615 N From A Second Charge 92 That Is 0750 M Away What Is The Value Of 92 Include The Sign Of The Charge Or U Stan class=

Sagot :

Eduard22slyidn

Answer:

+1.46×10¯⁶ C

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = +26.3 μC = +26.3×10¯⁶ C

Force (F) = 0.615 N

Distance apart (r) = 0.750 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Charge 2 (q₂) =?

The value of the second charge can be obtained as follow:

F = Kq₁q₂ / r²

0.615 = 9×10⁹ × 26.3×10¯⁶ × q₂ / 0.750²

0.615 = 236700 × q₂ / 0.5625

Cross multiply

236700 × q₂ = 0.615 × 0.5625

Divide both side by 236700

q₂ = (0.615 × 0.5625) / 236700

q₂ = +1.46×10¯⁶ C

NOTE: The force between them is repulsive as stated from the question. This means that both charge has the same sign. Since the first charge has a positive sign, the second charge also has a positive sign. Thus, the value of the second charge is +1.46×10¯⁶ C

Llamadude0324idn

Answer:

+1.46

Explanation:

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