Answered

Discover new information and get your questions answered with IDNLearn.com. Get the information you need from our community of experts who provide accurate and thorough answers to all your questions.

2.0 L of oxygen gas and 8.0 L of nitrogen gas at STP are mixed together. The gaseous mixture is compressed to occupy 2.0 L at 298 K. What is the pressure exerted by this mixture?

Sagot :

Dsdrajlinidn

Answer:

5.5 atm

Explanation:

Step 1: Calculate the moles in 2.0 L of oxygen at STP

At STP, 1 mole of an ideal gas occupies 22.4 L.

2.0 L × 1 mol/22.4 L = 0.089 mol

Step 2: Calculate the moles in 8.0 L of nitrogen at STP

At STP, 1 mole of an ideal gas occupies 22.4 L.

8.0 L × 1 mol/22.4 L = 0.36 mol

Step 3: Calculate the total number of moles of the mixture

n = 0.089 mol + 0.36 mol = 0.45 mol

Step 4: Calculate the pressure exerted by the mixture

We will use the ideal gas equation.

P × V = n × R × T

P = n × R × T / V

P = 0.45 mol × (0.0821 atm.L/mol.K) × 298 K / 2.0 L = 5.5 atm

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Thank you for visiting IDNLearn.com. We’re here to provide dependable answers, so visit us again soon.