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A sample of gas occupies a volume of 27 mL at a temperature of 161K. What is the volume of the temperature if raised to 343K?

Sagot :

Answer: The  volume is 57.52 mL if the temperature if raised to 343K.

Explanation:

Given: [tex]V_{1}[/tex] = 27 mL,       [tex]T_{1}[/tex] = 161 K

[tex]V_{2}[/tex] = ?,        [tex]T_{2}[/tex] = 343 K

According to Charles law, at constant pressure the volume of an ideal gas is directly proportional to temperature.

Formula used is as follows.

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{27 mL}{161 K} = \frac{V_{2}}{343 K}\\V_{2} = 57.52 mL[/tex]

Thus, we can conclude that volume is 57.52 mL if the temperature if raised to 343K.