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Sagot :
Answer:
(fill in blanks in order)
4, 16, 36, 64, 100, 144...
Step-by-step explanation:
You need to calculate.
So plug in the Time in Seconds for t
You are solving for D, trying to find distance.
D= 16(0.5)²
solve with PEMDAS (and calculator)
0.5²= 0.25
D=16(0.25)
16 * 0.25= 4
D=4 FOR THE FIRST BLANK
________________________________
Now continue....
D=16(1)²
1^2 is just 1
16(1) is just 16
D=16
_____________
D=16(1.5)^2
1.5^2= 2.25
16(2.25)= 36
D=36
_______________
D=16(2)^2
2^2= 4
16(4)= 64
D= 64
_____________
D=12(2.5)^2
2.5^2= 6.25
16(6.25)= 100
D=100
______________
D=16(3)^2
3^2= 9
16(9)= 144
D=144
________________
NOW YOU KEEP GOING, NOW YOU KNOW WHAT THEY ARE ASKING.
For the next question, you have to go back and find that original table and compare.
Hi there!
The question gives us the equation [tex]D=16t^2[/tex] to describe the scenario of a stone dropping. D represents distance in feet and t represents time in seconds.
For example, to find the distance of how far the stone fell after 1 second of dropping it, we plug in 1 as t in the equation:
[tex]D=16t^2\\D=16(1)^2\\D=16(1)\\D=16[/tex]
Therefore, after 1 second of being dropped, the stone fell 16 feet.
Now, because we know this, we can fill in the blank under the "1" in the table for "Distance stone fell in feet."
To fill in the rest of the blanks, repeat this process but with different values of t.
For example, to find how far the stone fell after 0.5 seconds of dropping it, we plug in 0.5 as t in the equation:
[tex]D=16t^2\\D=16(0.5)^2\\D=16(0.25)\\D=4[/tex]
Therefore, after 0.5 seconds of being dropped, the stone fell 4 feet.
Now, we can fill in the blank under the "0.5" in the table for "Distance stone fell in feet."
Repeat this for 1.5-4 values of t (as given in the table).
Then, for part a), compare the table after you've filled it out to the table from Lesson 1.
I hope this helps!
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