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Solve the systems of equations using substitution.
y=8x+1
y=6x+3
(0,1)
(1,9)
(4, 14)
(2, 4)

Sagot :

Bisratabrhamidn

Answer:

y= 8x+1 (0,1) y=6x+3 (0,1)

= 8×0+1 =6×0+3

y = 1 =3

Step-by-step explanation:

= 8×1+1 (1,9) =6×1+3 (1,9)

y=9 =9

=8×4+1 (4,14) =6×4+3 (4,14)

y=33 =27

=8×2+1(2,4) =6×2+1 (2,4)

y=17 =13

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