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Find four consecutive even integers such that if the sum of the first and third was multiplied by 2, the result is 20 less than three times the fourth.

Sagot :

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xAnswer:

-10   -8   -6   -4

Step-by-step explanation:

The numbers are  

first =x

second= x+2

third=x+4

4th= x+6

2(x + (x+4)) = 3(x+6)-20

4x+8 = 3x+18–20

4x-3x=18–20–8

x=-10

So the numbers are       -10,           -8,              -6,            -4

                                       first           2nd          3rd             4th

           Check:

         2( -10-6)  = 3(-4) -20

            2(-16) =  -12-20

-32 = -32

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