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Answer:
[tex]B. 4x^2+76=32[/tex]
Step-by-step explanation:
[tex]In ~ option~ B[/tex]
[tex]4x^2+76=32\\[/tex]
[tex]4x^2=-76+32[/tex]
[tex]4x^2=-44[/tex]
[tex]x^2=-44/4=-11[/tex]
[tex]x^2=-11[/tex]
A square of any real number can't be a negative integer.
So, Option B is your answer
[tex]--------------[/tex]
hope it helps..
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