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PLZZZZ HELPPPP :(
The area of a triangle is 8 square units. A second triangle has side lengths 5 times those of the first triangle. What is the area, in square units of the second triangle? ( The area of a triangle with base and height is equal to 1 /2 bh .


Sagot :

Answer:

40

Step-by-step explanation:

The area of the second triangle is 200 square unit.

Given:

the area of the first triangle, A = 8 square unit

let the base of the first triangle = b

let the height of the first triangle = h

then, base of the second triangle = 5b

height of the second triangle = 5h

To find:

the area of the second triangle

The area of the first triangle is given as;

[tex]A = \frac{bh}{2} \\\\2A = bh\\\\2(8) = bh\\\\16 = bh ---- (1)[/tex]

The area of the second triangle is calculated as;

[tex]A = \frac{5b \times 5h}{2} \\\\A = \frac{25bh}{2} \\\\recall, bh = 16\\\\A = \frac{25 \times 16}{2} \\\\A = 200 \ unit^2[/tex]

Thus, the area of the second triangle is 200 square unit.

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