Answer:
For the second to last problem the coefficients is 1, 5, 3, and 4 and the last problem all the coefficients are 1's
Explanation:
For the second to last problem you put 3 next to CO₂ so C is 3 on both sides. Then you put 4 next to H₂O because H will then be 8 on both sides. Lastly you put 5 next to O₂ which will make 10 on the reactant side. On the product side the 3 next to CO₂ will make O on the product side 6 and the 4 next to H₂O will make O on the product side 4. You will then add both together and it will make 10, which will make 10 on both sides. Hope this helps!
