Answered

Discover how IDNLearn.com can help you find the answers you need quickly and easily. Our experts provide timely, comprehensive responses to ensure you have the information you need.

When methane is burned with oxygen, the products are carbon dioxide and water, If you produce 20 grams of water and 10 grams of carbon dioxide from 15 grams of oxygen, how many grams of methane were needed for the reaction?​

Sagot :

When methane is burned with oxygen, the products are carbon dioxide and water. If you produce 9 grams of water and 11 grams of carbon dioxide from 16 grams of oxygen, how many grams of methane were needed for the reaction? First you need to write a balanced chemical equation.
Laylarodriguez892idn

Answer:

4 g

Explanation:

First you need to write a balanced chemical equation. You are given thatmethane is burned, meaning a combustion reaction in which carbon dioxide and water are released.

Unbalanced: CH4 + O2 ---> CO2 + H2O

Balanced: CH4 + 2O2 ---> CO2 + 2H2O

Givens:

X grams CH4 (Molecular mass 16.0 grams)

9 grams H2O (Molecular mass 18.0 grams)

11 grams CO2 (Molecular mass 44.0 grams)

Mole ratio: 1:2:1:2 (CH4:O2:CO2:H2O)

Then you need to find which of the reactants are the limiting reactant and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.

11 g CO2 / (44.0 g) = 0.25 moles CO2

9 g H2O / (18.0 g) = 0.5 moles

n of CH4 = n of CO2 = n of H2O /2 = 0.25 moles

m of CH4 = n* Mw = 0.25 * 16.0 = 4 g

Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Thank you for visiting IDNLearn.com. We’re here to provide accurate and reliable answers, so visit us again soon.