Answered

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C++ Add each element in origList with the corresponding value in offsetAmount. Print each sum followed by a semicolon (no spaces).

Ex: If origList = {4, 5, 10, 12} and offsetAmount = {2, 4, 7, 3}, print:
6;9;17;15;

#include
#include
using namespace std;

int main() {
const int NUM_VALS = 4;
int origList[NUM_VALS];
int offsetAmount[NUM_VALS];
int i;

cin >> origList[0];
cin >> origList[1];
cin >> origList[2];
cin >> origList[3];

cin >> offsetAmount[0];
cin >> offsetAmount[1];
cin >> offsetAmount[2];
cin >> offsetAmount[3];

/* Your code goes here */

cout << endl;

return 0;
}

Sagot :

Phenom786idn

Answer:

here you go, if it helps ,do consider giving brainliest

Explanation:

#include<stdio.h>

int main(void)

{

  const int NUM_VALS = 4;

  int origList[4];

  int offsetAmount[4];

  int i = 0;

  origList[0] = 40;

  origList[1] = 50;

  origList[2] = 60;

  origList[3] = 70;

  offsetAmount[0] = 5;

  offsetAmount[1] = 7;

  offsetAmount[2] = 3;

  offsetAmount[3] = 0;

  // Prints the Sum of each element in the origList

  // with the corresponding value in the

  // offsetAmount.

  for (i = 0;i<NUM_VALS;i++)

  {

      origList[i] += offsetAmount[i];

      printf("%d ", origList[i]);

  }

  printf("\n");

  return 0;

}

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