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Is the point (4,0) on the parabola given by the equation: y=x^2-4x? Explain your answer
HELPP PLEASE ILL MARK BRAINIEST


Sagot :

Give the point (4,0) you’re going to substitute those given numbers into the equation so, 0=4^2-4(4) now we know four squared is 16 and negative times a positive is negative 16 so 0=16-16, 0=0 this is true. Point (4,0) is indeed on the parabola