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Sagot :
Answer:
[tex](a)\ C(x) = 6312.50 + 8.75x[/tex]
[tex](b)\ R(x) = 34x[/tex]
[tex](c)\ P(x) = 6312.50 -25.25x[/tex]
[tex](d)\ Break\ Even = 250\ hours[/tex]
Step-by-step explanation:
Solving (a): The cost function.
Given
[tex]Cost = \$6312.50[/tex] --- cost of saxophone
[tex]Additional = \$8.75[/tex] per hour
The cost function is: sum of the cost of the saxophone and the extra cost per hour.
If an hour costs 8.75, then x hours will cost 8.75x
So, the cost function is:
[tex]C(x) = Cost + Additional[/tex]
[tex]C(x) = 6312.50 + 8.75x[/tex]
Solving (b): The revenue function
Given
[tex]Charges = \$34.00[/tex] per hour
The revenue function is the product of the unit charge by the number of hours.
If in an hour, she charges $34.00, then in x hours, she will cost 34x
So, the revenue function is:
[tex]R(x) = Charges * Hours[/tex]
[tex]R(x) = 34.00 * x[/tex]
[tex]R(x) = 34x[/tex]
Solving (c): The profit function
This is the difference between the cost function and the revenue function
i.e.
[tex]P(x) = C(x) - R(x)[/tex]
So, we have:
[tex]P(x) = 6312.50 + 8.75x - 34x[/tex]
[tex]P(x) = 6312.50 -25.25x[/tex]
Solving (d): The break even hours.
To do this, we simply equate the cost function and the revenue function, then solve for x
i.e.
[tex]C(x) =R(x)[/tex]
[tex]6312.50 + 8.75x = 34x[/tex]
Collect like terms
[tex]6312.50 =- 8.75x + 34x[/tex]
[tex]6312.50 = 25.25x[/tex]
Solve for x
[tex]x = \frac{6312.50}{25.25}[/tex]
[tex]x = 250[/tex]
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