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Sagot :
Answer:
[tex]x \approx 729[/tex]
Step-by-step explanation:
Given
Let the number be x
So:
[tex]x + 10\sqrt x = 1000[/tex]
Required
Using trial and improvement, find x
This implies that we keep guessing the values of x until we get a value that match the equation.
Let
[tex]x = 625[/tex]
So, we have:
[tex]x + 10\sqrt x = 1000[/tex]
[tex]625 + 10 *\sqrt{625}[/tex]
Take the square root of 625
[tex]625 + 10 *\sqrt{625} = 625 + 10 *25[/tex]
[tex]625 + 10 *\sqrt{625} = 625 + 250[/tex]
[tex]625 + 10 *\sqrt{625} = 875[/tex]
Let
[tex]x = 729[/tex]
So, we have:
[tex]x + 10\sqrt x = 1000[/tex]
[tex]729 + 10 * \sqrt{729}[/tex]
Take the square root of 729
[tex]729 + 10 * \sqrt{729} = 729 + 10 * 27[/tex]
[tex]729 + 10 * \sqrt{729} = 729 + 270[/tex]
[tex]729 + 10 * \sqrt{729} = 999[/tex]
At this point, we can conclude that x is approximately 729 because
[tex]999 \approx 1000[/tex]
So:
[tex]x \approx 729[/tex]
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