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Fe2O3 + 6HCl → 2FeCl3 + 6H20 How many atoms of FeCl3 will be produced if 9.3 x 1023 atoms of HCl are used for this reaction? 6.7 x 1023 atoms FeCl3 3.1 x 1023 atoms FeCl3 9.3 x 1023 atoms FeCl3 1.2 x 1023 atoms FeCl3​

Sagot :

Maacastrobridn

Answer:

3.1x10²³

Explanation:

I'm going to answer the question assuming the number of molecules of FeCl₃ is asked, rather than the number of atoms.

  • Fe₂O₃ + 6HCl → 2FeCl₃ + 6H₂O

First we convert 9.3x10²³ atoms of HCl into moles of HCl, using Avogadro's number:

  • 9.3x10²³ atoms ÷ 6.023x10²³ atoms/mol = 1.54 mol HCl

Then we convert 1.54 moles of HCl into moles of FeCl₃, using the stoichiometric coefficients of the reaction:

  • 1.54 mol HCl * [tex]\frac{2molFeCl_3}{6molHCl}[/tex] = 0.51 mol FeCl₃

Finally we calculate how many FeCl₃ molecules are there in 0.51 moles:

  • 0.51 mol * 6.023x10²³ molecules/mol = 3.4x10²³ molecules

The closest option is 3.1x10²³.

The number of atoms produced is four times the number of FeCl₃ molecules produced.

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