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CF4 + Br2 CBr4 + F2

Mole Ratio?
How many moles of F2 can you make from 57 g of CF4?
How many grams of Br2 do you have if you made 250 g of CBr4?
How many moles of F2 can you make from 4.8 mol of CF4?

Sagot :

Jufsanabriasaidn

Answer:

Answers are in the explanation

Explanation:

Based on the reaction:

CF₄ + 2Br₂ → CBr₄ + 2F₂

The mole ratio of CF₄ is:

CF₄:Br₂ = 1:2

CF₄:CBr₄ = 1:1

CF₄:F₂ = 1:2

Moles F2:

Molar mass CF₄: 88.0g/mol

57.0g * (1mol / 88.0g) = 0.6477 moles CF₄ * (2mol F₂ / 1mol CBr₄) =

1.30 moles F₂

Mass Br2:

Molar mass CBr₄: 331.63g/mol

250.0g * (1mol / 331.63g) = 0.7539 moles CBr₄ * (2mol Br₂ / 1mol CF₄) =

1.51 moles Br₂ * (159.808g / mol) =

241g Br2

Moles F2:

4.8 moles CF₄ * (2mol F₂ / 1mol CF₄) =

9.6 moles F₂

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