Given:
[tex]m\angle B=90^\circ, m\angle D=90^\circ, AB=x, BD=9, BC=1, DE=5[/tex].
To find:
The value of x.
Solution:
In triangles ABC and ADE,
[tex]\angle B\cong \angle D[/tex] (Right angles)
[tex]\angle A\cong \angle A[/tex] (Common angles)
[tex]\Delta ABC\sim \Delta ADE[/tex] (AA property of similarity)
We know that the corresponding sides of similar triangles are proportional. So,
[tex]\dfrac{AB}{AD}=\dfrac{BC}{DE}[/tex]
[tex]\dfrac{x}{x+9}=\dfrac{1}{5}[/tex]
On cross multiplication, we get
[tex]5x=x+9[/tex]
[tex]5x-x=9[/tex]
[tex]4x=9[/tex]
[tex]x=\dfrac{9}{4}[/tex]
[tex]x=2.25[/tex]
Therefore, the value of x is 2.25 units.
