IDNLearn.com connects you with a community of experts ready to answer your questions. Ask anything and receive prompt, well-informed answers from our community of experienced experts.
Sagot :
Answer:
E = 30.37 J
Step-by-step explanation:
Given that,
The spring constant of the spring, k = 300 N/m
The spring is stretched by 0.45 m, x = 0.45 m
We need to find the elastic energy stored in the spring. The formula for the elastic energy is given by :
[tex]E=\dfrac{1}{2}kx^2\\\\=\dfrac{1}{2}\times 300\times (0.45)^2\\\\=30.37\ J[/tex]
So, the required elastic energy is equal to 30.37 J.
Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. IDNLearn.com is committed to providing the best answers. Thank you for visiting, and see you next time for more solutions.
