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What is the y value where the hole is located in this equation. Show your work. f(x)= (4x-4) x (x-12)/(x-12)

Sagot :

Answer:

y = 44

Step-by-step explanation:

Given

f(x) = [tex]\frac{(4x-4)(x-12)}{x-12}[/tex] ← cancel the factor (x - 12)

     = 4x-4

Removing this factor creates a hole at

x - 12 = 0 ⇒ x = 12

Substitute x = 12 into the simplified f(x)

y = 4(12) - 4 = 48 - 4 = 44

That is hole at (12, 44 )

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