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Sagot :
Given:
Height of a man = [tex]61\dfrac{5}{12}[/tex] inches
Height of the daughter = [tex]58\dfrac{4}{9}[/tex] inches
To find:
How much taller is the man?
Solution:
It this problem, we need to find the difference between the heights of the man and his daughter.
Difference between the heights [tex]=61\dfrac{5}{12}-58\dfrac{4}{9}[/tex]
[tex]=\dfrac{732+5}{12}-\dfrac{522+4}{9}[/tex]
[tex]=\dfrac{737}{12}-\dfrac{526}{9}[/tex]
Taking LCM, we get
Difference between the heights [tex]=\dfrac{3(737)-4(526)}{36}[/tex]
[tex]=\dfrac{2211-2104}{36}[/tex]
[tex]=\dfrac{107 }{36}[/tex]
[tex]=2\dfrac{35 }{36}[/tex]
Therefore, the man is [tex]2\dfrac{35}{36}[/tex] inches taller than his daughter.
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