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Sagot :
Answer: 15.2
Step-by-step explanation:
(14)^2 + (6)^2 = c^2
196 + 36 = c^2
232 = c^2
Square root both sides
15.231546 = c
15.2 ≈ c
The distance of the straight line from the starting point by the is is 15.2 miles.
What is the distance of a point from a line?
The distance between a point and a line is the shortest distance between them.
Pythagoras Theorem
It states that if a triangle is right-angled (90 degrees), then the square of hypotenuse is equals to the sum of the squares of the other two sides.
Pythagoras Theorem Equation
If ΔOAB is a right angled triangle, right angle at A
then the Pythagoras equation will be
[tex]OB^{2} =AB^{2} +OA^{2}[/tex]
(where OB, OA and AB are the length of the sides of triangle OAB)
According to the question
We have to find ,the distance of straight line from the starting point.
From, the provided figure we can conclude that OB is the straight line whose distance to be find
In ΔOAB, we have
[tex]OB^{2} =OA^{2} +AB^{2}[/tex] (By Pythagoras theorem)
[tex]OB^{2} =14^{2} +6^{2}[/tex]
[tex]OB^{2} =196+36[/tex]
[tex]OB=\sqrt{232} \\OB= 15.23 miles[/tex]
[tex]OB=15.2 miles[/tex]
Hence, the distance of straight line from the starting point is 15.2 miles.
Learn more about Pythagoras theorem here:
https://brainly.com/question/343682
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