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The circle below is centered at the point (4,-3) and has a radius of length 3. What is its equation? 6 O A. (x - 4)2 + (y + 3)2 - 32 W O B. (x-3)2 + (y + 4)2 = 9 ОООО C. (X- 3)2 + (y - 4)2 = 9 D. (x + 4)2 + (y - 3)2 = 32. ​

The Circle Below Is Centered At The Point 43 And Has A Radius Of Length 3 What Is Its Equation 6 O A X 42 Y 32 32 W O B X32 Y 42 9 ОООО C X 32 Y 42 9 D X 42 Y 3 class=

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Answer:

[tex](x-4)^2+(y+3)^2=9[/tex]

Step-by-step explanation:

Standard Form equation of a circle with center (h, k) and radius r:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Plug in given values: h = 4, k = -3, r = 3.

[tex](x-4)^2+[y-(-3)]^2=3^2\\\\(x-4)^2+(y+3)^2=9[/tex]

The tricky part can be the sign in the y squard term:  y - (-3) = y + 3.

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