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Answer: The percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.
Explanation:
Given: Volume of solute = 120 mL
Volume of solvent = 350 mL
Now, total volume of the solution is as follows.
[tex]V_{total} = V_{solute} + V_{solvent}\\= 120 mL + 350 mL\\= 470 mL[/tex]
Let us assume that 100 mL of solution is taken and the amount of isopropyl alcohol present in it is as follows.
[tex]\frac{V_{solute}}{V_{total}} \times 100 mL\\\frac{120 mL}{470} \times 100 mL\\= 25.53 mL[/tex]
Hence, there is 25.53 mL isopropyl alcohol is present in 100 mL of solution. Therefore, %v/v is calculated as follows.
[tex]Percent (v/v) = \frac{25.53 mL}{100 mL}\\= 25.5%[/tex]
Thus, we can conclude that the percent by volume of isopropyl alcohol in a solution made by mixing 120 mL of the alcohol with enough water to make 350 mL of solution is 25.5%.
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