Answer:
Vertex → (x, y) = (− 3, − 4)
x intercepts → (x, y) = (−5, 0) and (−1, 0)
y intercept → (x, y) = (0, 5)
Step-by-step explanation:
Set y = 0 = ( x + 3)^2 − 4
Add 4 to both sides
4 = (x + 3)^2
Square root both sides
± 2 = x + 3
Subtract 3 from both sides
x = − 3 ± 2
x intercepts → (x, y) = (− 5, 0)
and
(− 1, 0)
You may if you so choose determine the vertex from this point
x vertex is midway between the x intercepts then by substitution determine y. The method I used later takes less work.
Given
y (x + 3)^2 − 4
x vertex = (-1) ×(+ 3) = − 3
y vertex = − 4
Vertex → (x, y) = (− 3, − 4)
y intercept = + 3^2 − 4 = 5
