Join IDNLearn.com and start exploring the answers to your most pressing questions. Get step-by-step guidance for all your technical questions from our dedicated community members.
Answer:
[tex]-8.34\times 10^{11}\ \text{J}[/tex]
Explanation:
m = Mass of satellite = 15000 kg
h = Distance above Earth = 800 km
R = Radius of Earth = 6371 km
M = Mass of Earth = [tex]5.972\times 10^{24}\ \text{kg}[/tex]
G = Gravitational constant = [tex]6.674\times 10^{-11}\ \text{Nm}^2/\text{kg}^2[/tex]
Potential energy is given by
[tex]U=-\dfrac{GMm}{R+h}\\\Rightarrow U=-\dfrac{6.674\times 10^{-11}\times 5.972\times 10^{24}\times 15000}{(6371+800)\times 10^3}\\\Rightarrow U=-8.34\times 10^{11}\ \text{J}[/tex]
The potential energy of the satellite is [tex]-8.34\times 10^{11}\ \text{J}[/tex].