Taking into account the reaction stoichiometry, 40 grams of O₂ are needed to react with 0.50 moles of C₂H₂.
Reaction stoichiometry
In first place, the balanced reaction is:
2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- C₂H₂: 2 moles
- O₂: 5 moles
- CO₂: 4 moles
- H₂O: 2 moles
The molar mass of the compounds is:
- C₂H₂: 26 g/mole
- O₂: 32 g/mole
- CO₂: 44 g/mole
- H₂O: 18 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- C₂H₂: 2 moles× 26 g/mole= 52 grams
- O₂: 5 moles× 32 g/mole= 160 grams
- CO₂: 4 moles× 44 g/mole= 176 grams
- H₂O: 2 moles× 18 g/mole= 36 grams
Mass of O₂ needed
The following rule of three can be applied: if by stoichiometry of the reaction 2 moles of C₂H₂ react with 160 grams of O₂, 0.50 moles of C₂H₂ react with how much mass of O₂?
[tex]mass of O_{2} =\frac{0.50 moles of C_{2} H_{2}x160 grams of O_{2} }{2 moles of C_{2} H_{2}}[/tex]
mass of O₂= 40 grams
Finally, 40 grams of O₂ are needed to react with 0.50 moles of C₂H₂.
Learn more about the reaction stoichiometry:
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