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If your end product is 1.5 moles of KMnO 4 how many moles of manganese oxide were used in the reaction? The equation for the production of potassium pemanganate is as follows 2 MnO 2 +4 KOH+O 2 2 KMnO 4 +2 KOH+H 2

Sagot :

Answer:

1.5 moles

Explanation:

The equation of the reaction is given as:

2 MnO2 + 4 KOH + O2 --> 2KMnO 4 + 2KOH + H2

From the equation,

2 moles of MnO2 produces 2 moles of KMnO4

x moles of MnO2 would produce 1.5 moles of KMnO4

2 = 2

x = 1.5

Solving for x;

x = 1.5 * 2 / 2

x = 1.5 moles

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