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Answer:
Step-by-step explanation:
We know the perimeter of a triangle is the sum of all the sides( two legs and one hypotenuse).
By pythagoras we know that
[tex]h^2= a^2+b^2.[/tex]
and the perimeter is [tex]P=h+a+b[/tex].
Since P=24 and a=6 we have these equations:
[tex]h^2=36+b^2\\24=h+6+b[/tex]
From the last equation we have [tex]h=18-b[/tex]. Replace h in the first equation we get that
[tex](18-b)^2=36+b^2[/tex]
[tex]18^2-36b+b^2=36+b^2\\288=36b\\b=\frac{288}{36}=8[/tex]
and h=18-8=10