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In 2.20 liters of 1.50 molar sodium-chloride aqueous solution, there are 3.30 moles of chloride ions.
Molarity is the number of moles of solute per liter of solution.
We have 2.20 L of a 1.50 M solution.
2.20 L × 1.50 mol NaCl/L = 3.30 mol NaCl
The molar ratio of NaCl to Cl⁻ is 1:1.
3.30 mol NaCl × 1 mol Cl⁻/1 mol NaCl = 3.30 mol Cl⁻
In 2.20 liters of 1.50 molar sodium-chloride aqueous solution, there are 3.30 moles of chloride ions.
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