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Answer:
35% is the probability that the woman is a carrier of the deafness allele
Explanation:
Both man and woman have normal hearing
Woman's father has autosomal dominant sensory-neural deafness - Dd
Genotype of heterozygous Woman's father = Dd
Let us assume that woman’s mother has normal hearing = dd
Dd * dd
Dd, Dd, dd, dd
Two deaf and two normal offspring.
Since the penetration is of 70%, the probability of woman being a carrier is
½ * 70% = 0.35