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Sagot :
Answer:
Part A
a. There is not sufficient sample evidence to conclude that the full-time placement rate is now less than 87% because the p-value is greater than 0.05
Part B
[tex]\hat Y[/tex] = 17.9·(x) + 1.6
Part C
The teen pregnancy rate in Florida is 6.54
Step-by-step explanation:
The percentage of graduates that find full-time employment in their fields within the first year of graduation = 87%
The significant level of the hypothesis test = 5% = 0.05
The p-value = 0.07
Given that the testing conditions are met, we have;
The p-value is larger than the significant level of 0.05, therefore, it cannot be concluded that there is significant difference between the two rates
Therefore;
There is not enough statistical evidence available to come to a conclusion that the placement rate of full-time students has reduced below the given 87% because from the statistics, the p-value is larger than 0.05.
Part B
Number of Pages, x; 7, 12, 4, 14, 25, 30
Cost, y; 128, 213, 75, 250, 446, 540
The regression analysis formula is;
Y = a + b·X
We have;
[tex]b = \dfrac{N\sum XY - \left (\sum X \right )\left (\sum Y \right )}{N\sum X^{2} - \left (\sum X \right )^{2}}[/tex]
∴ b = (6×34602-92×1652)/(6×1930 - 92²) ≈ 17.852
[tex]a = \dfrac{\sum Y - b\sum X}{N}[/tex]
a = (1652 - 17.852 × 92)/6 ≈ 1.6
∴ Y ≈ 17.9·(x) + 1.6
Part C
The given regression model is y = 4.3 + 1.4(x)
Therefore, at x = 1.6, we get;
y = 4.3 + 1.4 × 1.6 = 6.54
The suggests that the teen pregnancy rate in Florida is 6.54.
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