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Sagot :
[tex]8-2b=-\dfrac{2}{3}(12b+6)\\ 8-2b=-8b-4\\ 6b=-12\\ b=-2\\\\ -5=\dfrac{8m+12}{4}\\ -5=2m+3\\ 2m=-8\\ m=-4\\\\ -12j+4=-4-12j\\ 4=-4\\ j\in\emptyset \Rightarrow A [/tex]
[tex]5x+7=\dfrac{1}{2}(10x+12)\\ 5x+7=5x+6\\ 7=6\\ x\in \emptyset \Rightarrow B\\\\ -\dfrac{1}{9}(18x+27)=1+x-4-3x\\ -2x-3=-2x-3\\ 0=0\\ x\in\mathbb{R} \Rightarrow C\\\\ \dfrac{x+3}{4}=\dfrac{3}{4}x+\dfrac{3}{4}|\cdot4\\ x+3=3x+3\\ -2x=0\\ x=0 \Rightarrow A\\\\ 4+3x=2x-10\\ x=-14 \Rightarrow A [/tex]
[tex]5x+7=\dfrac{1}{2}(10x+12)\\ 5x+7=5x+6\\ 7=6\\ x\in \emptyset \Rightarrow B\\\\ -\dfrac{1}{9}(18x+27)=1+x-4-3x\\ -2x-3=-2x-3\\ 0=0\\ x\in\mathbb{R} \Rightarrow C\\\\ \dfrac{x+3}{4}=\dfrac{3}{4}x+\dfrac{3}{4}|\cdot4\\ x+3=3x+3\\ -2x=0\\ x=0 \Rightarrow A\\\\ 4+3x=2x-10\\ x=-14 \Rightarrow A [/tex]
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