[tex]\frac{2}{3}x-9=\frac{3}{4}\ \ \ \ |multiply\ both\ sides\ by\ LCM(3;4)=12\\\\12\cdot\frac{2}{3}x-12\cdot9=12\cdot\frac{3}{4}\\\\4\cdot2x-108=3\cdot3\\\\8x-108=9\ \ \ \ |add\ 108\ to\ both\ sides\\\\8x=117\ \ \ \ |diviede\ both\ sides\ by\ 8\\\\x=\frac{117}{8}\\\\\boxed{x=14\frac{5}{8}}[/tex]
[tex]\frac{1}{5}x+8=\frac{3}{4}\ \ |other\ method\ like\ first\ . . . . |subtract\ 8\ from\ both\ sides\\\\\frac{1}{5}x=\frac{3}{4}-8\\\\\frac{1}{5}x=\frac{3}{4}-\frac{4\cdot8}{4}\\\\\frac{1}{5}x=\frac{3}{4}-\frac{32}{4}\\\\\frac{1}{5}x=-\frac{29}{4}\ \ \ \ |divide\ both\ sides\ by\ \frac{1}{5}\to(multiply\ both\ sides\ by\ 5)\\\\x=-\frac{29}{4}\cdot\frac{5}{1}\\\\x=-\frac{145}{4}\\\\\boxed{x=-36\frac{1}{4}}[/tex]
