Get the best answers to your questions with the help of IDNLearn.com's experts. Discover comprehensive answers from knowledgeable members of our community, covering a wide range of topics to meet all your informational needs.
Sagot :
we must assume that he must put a whole number of objects in each wreath so we must find the greatest common factor
60=2 time 2 times 3 times 5
36=2 times 2 times 3 times 3
48=2 times 2 times 2 times 2 times 3
the factors are 2 times 2 times 3 or 12
there can be 12 wreath max
we total them up and divide by 12
60+36+48=144
144/12=12
12 items per wreath
60=2 time 2 times 3 times 5
36=2 times 2 times 3 times 3
48=2 times 2 times 2 times 2 times 3
the factors are 2 times 2 times 3 or 12
there can be 12 wreath max
we total them up and divide by 12
60+36+48=144
144/12=12
12 items per wreath
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. IDNLearn.com is your source for precise answers. Thank you for visiting, and we look forward to helping you again soon.