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the equation of a line?
passes through (-2,5) and is parallel to y-2/3x+1
y - 5 = m[ x - ( - 2 ) ] is the "point-slope" form of your staright - line equations; y - 5 = m( x + 2 ) ; But, your line is parallel to y = ( 2 / 3 )x + 1; m = 2 / 3; Finally, y - 5 = ( 2 / 3)( x + 2); y = 5 + ( 2 / 3)x + 4 / 3; y = ( 2 / 3 )x + 15 / 3 + 4 / 3 ; y = ( 2 / 3 )x + 19 / 3.
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