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A sample of a gas has a volume of 852 mL at 298 K. If the gas is cooled to 200K, what would the new volume be?

Sagot :

Maacastrobridn

Answer:

571.81 mL

Explanation:

Assuming constant pressure, we can solve this problem by using Charles' law, which states that at constant pressure:

  • V₁T₂=V₂T₁

Where in this case:

  • V₁ = 852 mL
  • T₂ = 200 K
  • V₂ = ?
  • T₁ = 298 K

We input the data:

  • 852 mL * 200 K = V₂ * 298 K

And solve for V₂:

  • V₂ = 571.81 mL

The new volume would be 571.81 mL.

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