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Find the number of x-interpects of y=-x^2+4x-12

Sagot :

Abidemiokinidn

Answer:

x = -2 + 2√2 i and -2 - 2√2 i

Step-by-step explanation:

Given the function, y=-x^2+4x-12

x intercept occurs at y =  0

Substitute y = 0

0=-x^2+4x-12

x^2 - 4x + 12 = 0

Factorize

x = -4±√4²-4(12)/2

x = -4±√16-48/2

x = -4±√-32/2

x = -4 ± √32 i/2

x = -4+4√2 i/2 and x =-4-4√2 i/2

x = -2 + 2√2 i and -2 - 2√2 i

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