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Find the equation of the line that
is perpendicular to y = -2x + 1
and contains the point (8, 2).
[?]
y =
x+ [

Find The Equation Of The Line That Is Perpendicular To Y 2x 1 And Contains The Point 8 2 Y X class=

Sagot :

Answer:

y=[tex]\frac{1}{2}x-2[/tex]

Step-by-step explanation:

Perpendicular lines have negative reciprocal gradients(slopes) so the slope of your new line would be 1/2. Then you use the point to find the new y-intercept

y=mx+b

2=[tex]\frac{1}{2}[/tex](8)+b

2=4+b

B=-2

y=[tex]\frac{1}{2}x-2[/tex]

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