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The formula for the area A of a trapezoid is shown below where h represents its height and b1 and b2 represent the lengths of its bases. for this problem let b1 represent the length of its shorter base. A=1/2h (b1+b2) which of the descriptions below is equivalent to the formula shown above?
A.The length of the longer base is equal to the quotient of twice the area and the height plus the length of the shorter base.
B.The height is equal to twice the area divided by the productof the lengths of the two bases.
C.The length of the longer base is equal to the quotient of the area and the height, minus half the length of the shortee base
D.The height is equal to twice the area divided by the sum of the lengths of the two bases.


The Formula For The Area A Of A Trapezoid Is Shown Below Where H Represents Its Height And B1 And B2 Represent The Lengths Of Its Bases For This Problem Let B1 class=

Sagot :

A = ( 1 / 2 ) h ( b1 + b2 ) ;
h = ( 2A) / ( b1 + b2 );
b2 = ( 2A / h) - b1 ;

D. is the right answer ; 

Option D is correct. The height is equal to the ratio of twice the area and the sum of the length of the bases.

The formula for calculating the area of a trapezoid is expressed as:

[tex]A= \frac{1}{2}(b_1+b_2)h[/tex] where:

[tex]b_1 \ and \ b_2[/tex] are the opposite sides of the trapezoid

h is the height of the trapezoid

Express the height "h" as a function of the rest

[tex]2A = (b_1+b_2)h\\h=\frac{2A}{b_1+b_2}[/tex]

This shows that the height is equal to the ratio of twice the area and the sum of the length of the bases.

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