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Sagot :
Answer:
Rmains constant
Explanation:
The equation of the trajectory of a projectile motion is presented as follows;
[tex]Y = x \cdot tan \theta -\dfrac{g \cdot x^2}{2 \cdot u^2 \cdot cos^2 \theta}[/tex]
The vertical componet of the prjectile motion is
y = (u·sinθ)·t - g·t²/2
Where;
θ = The angle with which the projectile is launched
x = The horizontal distance
u = The initial velocity of the projectile
g = The acceleration due to gravity = Constant
t = The time of motion
The acceleration acting on the projectile is the 'g' which is the constant acceleration due to gravity
Therefore, for general projectile motion with no air resistance, the vertical component of the projectile acceleration remains constant
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