Answered

Explore a vast range of topics and get informed answers at IDNLearn.com. Our experts provide timely and precise responses to help you understand and solve any issue you face.

Two arrows are shot vertically upward. The second arrow is shot after the first one, but while the first is still on its way up. the initial speeds are such that both arrows reach their maximum heights at the same instant, although these heights are different. Suppose the that initial speed of the first arrow is 34 m/s and that the second arrow is fired 0.204081632653061 seconds after the first. Determine the initial speed of the second arrow.

Sagot :

Numeniusidn

Answer:

The initial speed of the second arrow is 33.8 m/s.

Explanation:

initial speed of first arrow, u = 34 m/s

Let the initial height of the second arrow is h.

Let they both reaches at maximum height H.

Let the time taken by the first arrow is t and the second arrow is t - 0.0204

Let the initial speed of the second arrow is u'.

Use first equation of motion for the first arrow.

v = u - gt

0 = u - gt

34 = gt ..... (1)

For the second arrow

v =u' - g (t - 0.0204)

0 = u' - gt + 9.8 x 0.0204

u' = 34 - 0.1999 = 33.8 m/s

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and come back for more insightful information.