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Given f(x) = 3 and g(x) = cos(x). What is Limit of left-bracket f (x) minus g (x) right-bracket as x approaches negative pi?

Given Fx 3 And Gx Cosx What Is Limit Of Leftbracket F X Minus G X Rightbracket As X Approaches Negative Pi class=

Sagot :

Answer:

C

cos pie= -1

so (3-(-1)=3+1=4

Step-by-step explanation: