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Sagot :
Answer:
C₂H₆O
Explanation:
Empirical formula is the simplest ratio of atoms present in a molecule. To solve this question we must find the moles of C, H and O in order to find the simplest ratio of this atoms.
To solve this question we must find the moles of C from CO2, moles of H from H2O and moles of O from the difference of masses of C and H and the sample:
Moles C:
1.64g CO2 * (1mol / 44g) = 0.03727 moles CO2 * (1mol C / 1mol CO2) = 0.03727 moles C
0.03727 moles C * (12g / mol) = 0.4473g C
Moles H:
1.01g H2O * (1mol / 18g) = 0.05611 moles H2O * (2mol H / 1mol H2O) =
0.1122 moles H
0.1122 moles H * (1g / mol) = 0.1122g H
Moles O:
0.860g - 0.1122g H - 0.4473g C = 0.3005g O * (1mol / 16g) =
0.01878 moles O
The ratio of the moles of atoms regard to the moles of O (Lower number of moles) is:
C = 0.03727 moles C / 0.01878 moles O = 1.98 ≈ 2
H = 0.1122 moles H / 0.01878 moles O = 5.97 ≈ 6
O = 0.01878 moles O / 0.01878 moles O = 1
Empirical formula is:
C₂H₆O
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