Answer:
Radius of the circle is 5 units.
Step-by-step explanation:
JKLMN is a regular polygon inscribed in a circle.
Since, its a regular polygon,
JN = NM = 5.88 units
"Perpendicular drawn from the center of the circle to any chord is the bisector of the chord"
Therefore, PQ will be the perpendicular bisector of chord NM.
QM = [tex]\frac{1}{2}(NM)[/tex]
QM = [tex]\frac{1}{2}(5.88)[/tex]
QM = 2.94 units
By applying Pythagoras theorem in ΔPQM,
PM² = PQ² + QM²
PM² = (4.05)² + (2.94)²
PM = [tex]\sqrt{16.4025+8.6436}[/tex]
PM = [tex]\sqrt{25.0461}[/tex]
PM = 5 units
Therefore, radius of the circle is 5 units.
