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Answer:
3600 J
Explanation:
According to given question
P(rated)=60w
V= 120
I =0.50 A
t=600 second
Now,
Energy can be calculated as :
[tex]E= VI*t[/tex]
Where,
V is voltage
I is current
t is time in second
Now,
Putting the all value in above equation E
So,
[tex]E=120*0.5*600\\E=36000 J[/tex]
Therefore, 36000 J energy use up by light bulb