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A disk initially rotates counterclockwise at 1.0 rad.S but has a counterclockwise angular acceleration of 0.50rad/s^2 for 2.0s after this acceleration the disk is at an angle of 6.0 what us the disk angular position when the acceleration started

Sagot :

Answer:

Explanation:

initial angular velocity is ω₀ = 1 rad /s

angular acceleration α = - 0.5 rad /s²

time t = 2 s.

Let the initial angular position be θ .

angular displacement = 6 - θ . rad .

angular displacement = ω₀ t - 1/2 α t²

6 - θ = 1 x 2 - 0.5 x 0.5 x 2²

6 - θ = 2  - 0.5 x 0.5 x 2²

= 2 - 1 = 1

θ = 6 - 1 = 5

5 rad is the answer.

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